1.

Magnetic flux linked with one closed conducting loop is phi=t^2+3t-7. Then graph of epsilon to t would be a ..... (All the values are in SI units)

Answer»

circle
parabola
ellipse
straight LINE

Solution :Here `phi=t^2+3t-7`
`therefore (dphi)/(dt)=2t+3`
`therefore epsilon=-(dphi)/(dt)=(-2)t+(-3)`
Above equation is of the FORM y = MX + c which is equation of a straight line.


Discussion

No Comment Found

Related InterviewSolutions