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Magnetic field due to 0.1 A current flowing through a circular coil of radius 0.Im and 1000 turns at the centre of the coil is |
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Answer» We know that B = m Ni/2r B = 4PI × 10^-7 ×1000 ×0.1/2×0.1 B = 2 pi × 10^-4 PUT value of pi B = 2×3.14×10^-4 B = 6.28×10^-4 |
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