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Magnetic field at the center (at nucleus) of the hydrogen like atom `("atomic number" = z)` due to the motion of electron in nth orbit is proporional toA. `(n^(2))/(z^(3))`B. `(n^(4))/(Z)`C. `(z^(2))/(n^(3))`D. `(z^(3))/(n^(5))` |
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Answer» Correct Answer - 4 Current produced orbiting `e^(-)` is `I =(qv)/(2pir)` `therefore` Magnetic field at centre `B =(mu_(0)i)/(2pi)=(mu_(0))/(2)((qv)/(2pir)) (1)/(r)`. `=(mu_(0) ev)/(4pir^(2))` As `V prop (Z)/(n) and r prop (n^(2))/(Z)`. `therefore B prop (Z)/(n)=(Z//n)((Z)/(n^(2)))^(2)` `B prop (Z^(3))/(n^(5))` |
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