Saved Bookmarks
| 1. |
m \text { so that }\left(\frac{2}{9}\right)^{3} \times\left(\frac{2}{9}\right)^{6}=\left(\frac{2}{9}\right)^{2 n-1} |
|
Answer» (2/9)^3 +( 2/9)^-6=(2/9)^2m-1(2/9)^-3=(2/9)^2m-12m-1=-32m=-2m=-1 |
|