1.

(m) length = 2 m 25 cm and breadth = 1 m 50 cm(iii) length = 8 m 5 dm and breadth = 6 m 8 dm2. Pind the cost of fencing a rectangular field 62 m long and 33 m wide at * 16 per metre3. The length and the breadth of a rectangular field are in the ratio 5:3. If its perimete128 m, find the dimensions of the field.4. The cost of fencing a rectangular field at 18 per metre is * 1980. If the width of the fie23 m, find its length.5. The length and the breadth of a rectangular field are in the ratio 7:4. The cost of fencinfield at 25 per metre is * 3300. Find the dimensions of the field.6. Find the perimeter of a square, each of whose sides measures:/3.8 cm(i) 4.6 mid) 2 m 5 dm7. The cost of putting a fence around a square field at 35 per metre is * 4480. Find theof each side of the field.8. Each side of a square field measures 21 m. Adjacent to this field, there is a rectangulahaving its sides in the ratio 4:3. If the perimeters of both the fields are equal, fidimensions of the rectangular field.9. Find the perimeter of(i) a triangle of sides 7.8 cm, 6.5 cm and 5.9 cm,(i) an equilateral triangle of side 9.4 cm.(iii) an isosceles triangle with equal sides 8.5 cm each and third side 7 cm.10. Find the perimeter of​

Answer»

Answer:

perimeter of RECTANGLE = 2(l+b)

= 2(62+33) = 190 m

cost of fancing = 16×190 = ₹3040 ...

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