1.

.m. grams of a gas of a molecular weight M is flowing in an isolated tube with velocity 2V. If the gasflow is suddenly stopped the rise in its temperature is, (gamma = ratio of specific heats, R = universal gas constant , J = Mechanical equivalent of heat)

Answer»

`(2Mv^2(GAMMA -1 ))/(RJ)`
`(mv^2 (gamma -1))/(M2RJ)`
`(mv^2 gamma)/(2RJ)`
`(Mv^2 gamma)/(2RJ)`

ANSWER :A


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