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M=-1,point (-2,-3apon 2) |
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Answer» Step-by-step explanation: maximum height can be attained only when the PROJECTILE is LAUNCHED at 90° threrfore , H= u^2/2g 25×2×9.8= u^2 490=u^2 7√10=u then for range , the maximum range OCCURS at 45° R = u^2/g R = 490/9.8 R = 50 m |
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