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LYNOMIALSEXE. Find the zeroes of the following quadthe zeroes and the coefficients.(i) x-2x -8(ii) 4

Answer»

x^2-2x-8=x^2-4x+2x-8=x(x-4)+2(x-4)=(x+2)(x-4)so zeros are x-4=0 x=4x+2=0 x=-2

again

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