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Lorentz force acting on a charged particle is zero. If electric field is 5V/m, then |(vecBxxvecV)|= ______ . |
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Answer» zero `0=q[vecE+(vecvxxvecB)]` `therefore0=[vecE+(vecvxxvecB)]` `THEREFORE-(vecvxxvecB)=vecE` `therefore(vecBxxvecv)=vecE""[becausevecvxxvecB=-(vecBxxvecv)]` `therefore(vecBxxvecv)=5` |
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