1.

Lorentz force acting on a charged particle is zero. If electric field is 5V/m, then |(vecBxxvecV)|= ______ .

Answer»

zero
infinite
5
none of these

Solution :LORENTZ FORCE `vecF=q[VECE+(vecvxxvecB)]`
`0=q[vecE+(vecvxxvecB)]`
`therefore0=[vecE+(vecvxxvecB)]`
`THEREFORE-(vecvxxvecB)=vecE`
`therefore(vecBxxvecv)=vecE""[becausevecvxxvecB=-(vecBxxvecv)]`
`therefore(vecBxxvecv)=5`


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