1.

Logx − log x − 1^2 = 2 log( x− 1)

Answer»

Answer:

I'll solve whatever I SEE here and understand:

logx - logx -1^2 = 2 log (X-1)

=> log x/(x-1) = log (x-1)^2

=> x/x-1 = 1/(x-1)^2

=> x(x-1) = 0

=> x =0 or x= 1


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