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log(x+y)=logx+logy,then x= |
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Answer» logx + logy = log(x+y) log(xy) = log(x+y) xy = x+y xy - y = x (x-1)y = x y = x/(x-1) logx + logy = log (x+y)log (xy) = log (x+y)xy =x+yxy-y=x(x-1)y=xy=x/(x-1) logx + lovy = log (x+y)log (xy) =log (x+y)xy = x+yxy - y = x(x-1)y=xy=x/(x-1) |
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