Log(x-y) =logx-logy show that y/ypower-1

1.	Log(x-y) =logx-logy show that y/ypower-1
Answer» Step-by-step EXPLANATION: LOG(x-y) =logx-logy $log(x - y) = log \frac{x}{y} \\ x - y = \frac{x}{y} \\ y(x - y) = x \\xy - {y}^{2} = x \\ xy - x = {y}^{2} \\ x(y - 1) = {y }^{2} \\ x = \frac{ {y}^{2} }{y - 1}$

Answer»

Step-by-step EXPLANATION:

LOG(x-y) =logx-logy

$log(x - y) = log \frac{x}{y} \\ x - y = \frac{x}{y} \\ y(x - y) = x \\xy - {y}^{2} = x \\ xy - x = {y}^{2} \\ x(y - 1) = {y }^{2} \\ x = \frac{ {y}^{2} }{y - 1}$

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Log(x-y) =logx-logy show that y/ypower-1​

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