Log (x-3) + log (x + 1) = log 3 + log (x-1) Por favor .... please

1.	Log (x-3) + log (x + 1) = log 3 + log (x-1) Por favor .... please
Answer» Answer: log_10(x+3)+log_10(x)=1->log_10((x+3)(x))=1->log_10x^2+3x=1->10^1=x^2+3x 0=x^2+3x-10->0=(x+5)(x-2)->x=-5,x=2 Step-by-step EXPLANATION: Use the property of LOGARITHM for log of a product is the SUM of the logs to change the sum to a product. Then use the definition to change from logarithmic FORM to exponential form then solve for x.

Answer»

Answer:

log_10(x+3)+log_10(x)=1->log_10((x+3)(x))=1->log_10x^2+3x=1->10^1=x^2+3x

0=x^2+3x-10->0=(x+5)(x-2)->x=-5,x=2

Step-by-step EXPLANATION:

Use the property of LOGARITHM for log of a product is the SUM of the logs to change the sum to a product. Then use the definition to change from logarithmic FORM to exponential form then solve for x.

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Log (x-3) + log (x + 1) = log 3 + log (x-1) Por favor .... please

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