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| 1. |
log tanx |
| Answer» Assume tan x to be y then the question becomes to find the derivative of log y.Hence, d/dx log (tan x) = 1/tan x . d/dx (tan x) ( using d/dx log x = 1/x)= 1/tan x . sec2 x.= (cos x)/ (sin x). 1/ cos2x= 1/ sin x cos x | |