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\log \frac { a ^ { 2 } } { b c } + \log \frac { b ^ { 2 } } { c a } + \log \frac { c ^ { 2 } } { a b } = 0 |
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Answer» 2loga-logbc+2logb-logca+2logc-logab=logc+logc-logb-logc+logb+logb-logc-loga+logc+logc-loga-logb=0 |
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