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Log 25 log 49÷ log 5 log 7 |
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Answer» To SOLVE this QUESTION, we MUST KNOW that log25 = log5² = 2log5 log49 = log7² = 2log7 So log25log7 ÷ log5log7 = (2log5×2log7)÷(log5log7) = 2×2 = 4 |
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