ln given figure, find the area of shaded part If ABCD is a square of s

1.	ln given figure, find the area of shaded part If ABCD is a square of side 14 cm and APD and BPC are two semicircles.
Answer» Given: Side of square = 14 cm Diameter of semi circle (AD = CB) = 14 cm Radius of semicircle (R) = \(\frac { 14 }{ 2 }\) = 7 cm ∴ Area of square ABCD = (side)² = 14 × 14 = 196 cm² Area of semicircle = \(\frac { 1 }{ 2 }\)πr² \(\frac { 1 }{ 2 }\) × \(\frac { 22 }{ 7 }\) × 7 × 7 = 77 cm² Area of two semicircle =2 × 77 = 154 cm² ∴ Area of shaded part Area of square ABCD – Area of two semicircles = 196 – 154 = 42 cm² Thus area of shaded part 42 sq cm

ln given figure, find the area of shaded part If ABCD is a square of side 14 cm and APD and BPC are two semicircles.

Answer»

Given: Side of square = 14 cm

Diameter of semi circle (AD = CB) = 14 cm

Radius of semicircle (R) = \(\frac { 14 }{ 2 }\) = 7 cm

∴ Area of square ABCD = (side)²

= 14 × 14 = 196 cm²

Area of semicircle = \(\frac { 1 }{ 2 }\)πr²

\(\frac { 1 }{ 2 }\) × \(\frac { 22 }{ 7 }\) × 7 × 7 = 77 cm²

Area of two semicircle =2 × 77 = 154 cm²

∴ Area of shaded part Area of square ABCD – Area of two semicircles

= 196 – 154 = 42 cm²

Thus area of shaded part 42 sq cm