Ln(1-2v) = -2t solve it

1.	Ln(1-2v) = -2t solve it
Answer» ∫ (1+v)/(1–2v-v²)dvLet, 1–2v-v² = z(-2 -2v )dv = dzor, -2(1+v)dv = dz∫ (-1/2)dz/z = (-1/2) LN\|z\| + C= (-1/2)ln\| 1–2v-v²\| +c [C is INTEGRAL CONSTANT]

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Ln(1-2v) = -2t solve it​

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