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LLLLLLLL5.farmer has enough food to feed 20 animals in his cattle for days. How lowwould the food last if there were 10 more animals in his cattle! |
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Answer» Let the number of days be x. Given that he has enough food to feed 20 animals in his cattle for 6 days.Later on, 10 more animals were added. Therefore the number of days required to feed 30 animals: 20 * 6 = (20 + 10) * x 120 = 30 * x x = 120/30 = 4. Therefore the number of days = 4. 20*6=(20+10) *a120=30*aa=120/30a=4 |
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