1.

LLLLLLLL5.farmer has enough food to feed 20 animals in his cattle for days. How lowwould the food last if there were 10 more animals in his cattle!

Answer»

Let the number of days be x.

Given that he has enough food to feed 20 animals in his cattle for 6 days.Later on, 10 more animals were added.

Therefore the number of days required to feed 30 animals:

20 * 6 = (20 + 10) * x

120 = 30 * x

x = 120/30

= 4.

Therefore the number of days = 4.

20*6=(20+10) *a120=30*aa=120/30a=4



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