List I has four entries and List II has five entries. Each entry of List I is to be matched with one or more than one entries of List II. List IList II (A)Centre(s) of the circle(s) having radius 5 and(P)(4,6)touching the line 3x+4y−11=0 at (1,2) is (are)(B)End points of one of the diameters of(Q)(1,1)x2+y2−6x−8y+20=0 are(C)The line equidistant from both the lines(R)(3,−3)4x+2y+2=0 and 6x+3y−21=0,passes through(D)If one of the sides of a square is 3x−4y−12=0(S)(−2,7)and its centre is (0,0), then its diagonalpasses through(T)(−2,−2) Which of the following is the only CORRECT combination?

List I has four entries and List II has five entries. Each entry of Li

1.	List I has four entries and List II has five entries. Each entry of List I is to be matched with one or more than one entries of List II. List IList II (A)Centre(s) of the circle(s) having radius 5 and(P)(4,6)touching the line 3x+4y−11=0 at (1,2) is (are)(B)End points of one of the diameters of(Q)(1,1)x2+y2−6x−8y+20=0 are(C)The line equidistant from both the lines(R)(3,−3)4x+2y+2=0 and 6x+3y−21=0,passes through(D)If one of the sides of a square is 3x−4y−12=0(S)(−2,7)and its centre is (0,0), then its diagonalpasses through(T)(−2,−2) Which of the following is the only CORRECT combination?
Answer» $List I$ has four entries and $List II$ has five entries. Each entry of $List I$ is to be matched with one or more than one entries of $List II .$ $\begin{matrix} List I & List II (A) & Centre(s) of the circle(s) having radius 5 and & (P) & (4, 6) touching the line 3 x + 4 y - 11 = 0 at (1, 2) is (are) (B) & End points of one of the diameters of & (Q) & (1, 1) x^{2} + y^{2} - 6 x - 8 y + 20 = 0 are (C) & The line equidistant from both the lines & (R) & (3, - 3) 4 x + 2 y + 2 = 0 and 6 x + 3 y - 21 = 0, passes through (D) & If one of the sides of a square is 3 x - 4 y - 12 = 0 & (S) & (- 2, 7) and its centre is (0, 0), then its diagonal passes through (T) & (- 2, - 2) \end{matrix}$ Which of the following is the only CORRECT combination?