Lines whose equation are `(x-3)/2=(y-2)/3=(z-1)/(lamda)` and `(x-2)/3=(y-3)/2=(z-2)/3` lie in same plane, then. Angle between the plane containing both lines and the plane `4x+y+2z=0` isA. `(pi)/3`B. `(pi)/2`C. `(pi)/6`D. `cos^(-1)(1/(sqrt(186)))`

Lines whose equation are `(x-3)/2=(y-2)/3=(z-1)/(lamda)` and `(x-2)/3=

1.	Lines whose equation are `(x-3)/2=(y-2)/3=(z-1)/(lamda)` and `(x-2)/3=(y-3)/2=(z-2)/3` lie in same plane, then. Angle between the plane containing both lines and the plane `4x+y+2z=0` isA. `(pi)/3`B. `(pi)/2`C. `(pi)/6`D. `cos^(-1)(1/(sqrt(186)))`
Answer» Correct Answer - B Normal vector to plane containing lines is `vec(n)=\|(hati, hatj, hatk),(2, 3, -1),(3, 2, 3)\|=1hat(i)+6hatj-5hat(k)` So angle between planes `costheta=(4+6-10)/(sqrt(21)sqrt(62))=0impliestheta=(pi)/2`

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Lines whose equation are `(x-3)/2=(y-2)/3=(z-1)/(lamda)` and `(x-2)/3=(y-3)/2=(z-2)/3` lie in same plane, then. Angle between the plane containing both lines and the plane `4x+y+2z=0` isA. `(pi)/3`B. `(pi)/2`C. `(pi)/6`D. `cos^(-1)(1/(sqrt(186)))`

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