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Lines AB and CD pass through the center of the adjacent picture circle. if Know that angle dcb and angle abc |
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Answer»
Let AB be the chord of the given circle with centre O and a radius of 10 cm. Then AB =16 cm and OB = 10 cm From O, DRAW OM perpendicular to AB. We know that the perpendicular from the centre of a circle to a chord bisects the chord. ∴ BM = (162) cm=8 cm In the right ΔOMB, we have: OB2 = OM2 + MB2 (Pythagoras theorem) ⇒ 102 = OM2 + 82 ⇒ 100 = OM2 + 64 ⇒ OM2 = (100 - 64) = 36 ⇒ OM=36−−√ cm=6 cm Hence, the DISTANCE of the chord from the centre is 6 cm...... plzz mark as brainlist follow me follow itz CUTIE GIRL ❣️
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