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Line y=2x-b cuts the parabola `y=x^(2)-4x` at points A and B. Then the value of b for which `angleAOB` is a right is (where O is origin) _________ . |
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Answer» Correct Answer - 7 (7) The line is y=2x-b,i.e., `1=(2x-y)/(b)` Homogenizing parabola with line, we get `x^(2)-4x((2x-y)/(b))-y((2x-y)/(b))=0` Since `angleAOB=90^(@)` Coefficient of `x^(2)+"coefficient of "y^(2)=0` `or1-(8)/(b)+(1)/(b)=0` `orb=7` |
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