1.

Limit x tends to 5 x^2+3x-10 / x +5

Answer»
\lim_{x \to 5} \:  \frac{ {x}^{2}  + 3x - 10}{x + 5}  \\  = \lim_{x \to 5} \:  \frac{(x + 5)(x - 2)}{x + 5}  \\  = \lim_{x \to 5} \: (x - 2) = 5 - 2 = 3


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