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| 1. |
Limit x-->0 cose x - cotx ÷ x |
| Answer» Lim x-->0( 1/sinx-cosx/sinx)÷x...by taking Lcm...u will get 1-cosx/(sinx)x....we can write 1-cosx as 2sin^2x/2.....in denominator multiply and divide by x and 4..then put the limits....u will get the answer 1/2 | |