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Limit tending to o tanX upon sin 3x |
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Answer» Divide numerator and denominator by x ,Then ==> limit x->0 tanx/x/sin3x/x==> lim x->0 1/sin3x/x (lim y-->0 tany/y=1)Now multiply and divide denominator by 3==> lim x->0 1/sin3x*3/x*3==> lim x->0 1/1*3 (lim y-->0 siny/y=1)==> 1/3I hope, this will help you. 1/3 |
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