1.

limf(x) =x+x2  +x3  -3/x-1 where x tends to 1

Answer»

\(\underset{x\rightarrow 1}{lim}\) f(x) = \(\underset{x\rightarrow 1}{lim}\) \(\frac{x+x^2+x^3-3}{x-1}\) (0/0 type)

\(\underset{x\rightarrow 1}{lim}\) \(\frac{x^3+x^2+x-3}{x-1}\)

\(\underset{x\rightarrow 1}{lim}\) \(\frac{(x-1)(x^2+2x+3)}{x-1}\)

 = \(\underset{x\rightarrow 1}{lim}\)  (x2+2x+3)

= 12 + 2 x 1 + 3 (By taking limit)

= 1+2+3 = 6



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