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\lim _ { x \rightarrow a } \frac { ( 1 + x ) ^ { 6 } - 1 } { ( 1 + x ) ^ { 2 } - 1 } |
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Answer» by putting x=0 we will get 0/0 formso using L'hospital rulelim x->0 6(1+x)^5 / 2(1+x)=6/2=3 |
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