\lim _ { x \rightarrow 0 } \frac { \sin 3 x } { \log _ { e } ( 1 + 7 x – InterviewSolution

1.

\lim _ { x \rightarrow 0 } \frac { \sin 3 x } { \log _ { e } ( 1 + 7 x ) }

Answer»

if we substitute x=0 we will get 0/0 form sk using L'hospital rule lim x->0 3cos3x/(7/(1+7x)) = 3/7

any easy methods?

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