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\lim _{x \rightarrow 0} \frac{e^{x}+e^{-x}-2}{\cos 3 x-\cos 5 x} |
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Answer» if we put x=0 it will be in 0/0 form so using L'hospital rulelim x->0 (e^x-e^(-x))/(-3sin3x+5sin5x)if we put x=0 it will be in 0/0 form so using L'hospital rulelim x->0 (e^x+e^(-x))/(-9cos3x+25cos5x)=2/(-9+25)=2/16=1/8 |
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