lim┬(x→1) ( ax^2+bx+c/ cx^2 + bx + a ), a+b+c ≠0 – InterviewSolution

1.	lim┬(x→1) ( ax^2+bx+c/ cx^2 + bx + a ), a+b+c ≠0
Answer» put in the limitshencea1+b1+c/c1+b1+a=a+b+c/a+b+c=1

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