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Lim x--->0 (1-x)n-1/x |
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Answer» \(\lim\limits_{x \to 0}\frac{(1-x)^n-1}{x}\) (\(\frac{0}{0}\,case\)) = \(\lim\limits_{x \to 0}\frac{-n(1-x)^{n-1}}{1}\) = -n |
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