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Light of wavelength 5000 Å falls on a plane reflecting surface. What are the wavelength and frequency of the reflected light ? For what angle of incidence is the reflected ray normal to the incident ray ? |
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Answer» Solution :Here `lamda=5000` Å`=5000xx10^(-10)m=5xx10^(-7)m` `therefore` Wavelength of reflected LIGHT=Wavelength of incident light `lamda=5xx10^(-7)m` Frequency of reflected light `V=(c)/(lamda)=(3xx10^(8))/(5xx10^(-7))=6xx10^(14)Hz` As reflected ray is normal to incident ray, hence `anglei+angler=90^(@)` but `angler=anglei` `therefore anglei+anglei=2anglei=90^(@)impliesanglei=45^(@)`. |
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