Light falls from glass (μ= 1.5) to air. Find the angle of incidence for which the angle of deviation is 90°.

Light falls from glass (μ= 1.5) to air. Find the angle of incidence f

1.	Light falls from glass (μ= 1.5) to air. Find the angle of incidence for which the angle of deviation is 90°.
Answer» μ= 1.5d= 90°critical angle = SIN ⁻¹(1/(μ )= 41.80maximum DEVIATION which is possible is = 90- 41,80=47.2°so in the gase case total internal reflection UST have taken placedeviation = 180- 2i=902i=90i=45°

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Light falls from glass (μ= 1.5) to air. Find the angle of incidence for which the angle of deviation is 90°.

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