Let z0 be a root of the quadratic equation, x2 + x + 1 = 0. If z = 3 +

1.	Let z0 be a root of the quadratic equation, x2 + x + 1 = 0. If z = 3 + 6i z081 – 3i z093, then arg z is equal to :(1) π/4(2) π/6(3) π/3(4) 0
Answer» The correct option (1) π/4 Explanation: z₀³ = 1 ⇒ z = 3 + 6i – 3i = 3 + 3i ⇒ arg(z) = π/4

Let z0 be a root of the quadratic equation, x2 + x + 1 = 0. If z = 3 + 6i z081 – 3i z093, then arg z is equal to :(1) π/4(2) π/6(3) π/3(4) 0

Answer»

The correct option (1) π/4

Explanation:

z₀³ = 1 ⇒ z = 3 + 6i – 3i = 3 + 3i

⇒ arg(z) = π/4

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Let z0 be a root of the quadratic equation, x2 + x + 1 = 0. If z = 3 + 6i z081 – 3i z093, then arg z is equal to :(1) π/4(2) π/6(3) π/3(4) 0

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