Let y=y(x) be the solution of the differential equation ((x+2)e(y+1x+2 – InterviewSolution

1.	Let y=y(x) be the solution of the differential equation ((x+2)e(y+1x+2)+(y+1))dx=(x+2)dy, y(1)=1. If the domain of y=y(x) is an open interval (α,β), then \|α+β\| is equal to
Answer» Let $y = y (x)$ be the solution of the differential equation $((x + 2) e^{(\frac{y + 1}{x + 2})} + (y + 1)) d x = (x + 2) d y, y (1) = 1.$ If the domain of $y = y (x)$ is an open interval $(α, β),$ then $\| α + β \|$ is equal to

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