Let (x3+px2+2x−5)19(x2+qx−41)8(x4−x3+x−7)6=x97+391x96+a95x95+a – InterviewSolution

1.	Let (x3+px2+2x−5)19(x2+qx−41)8(x4−x3+x−7)6=x97+391x96+a95x95+a94x94+⋯a1x+a0 be an identity, where p,q,a95,…,a0 are integers. Then smallest positive value of p is
Answer» Let $(x^{3} + p x^{2} + 2 x - 5)^{19} (x^{2} + q x - 41)^{8} (x^{4} - x^{3} + x - 7)^{6} = x^{97} + 391 x^{96} + a_{95} x^{95} + a_{94} x^{94} + \dots a_{1} x + a_{0}$ be an identity, where $p, q, a_{95}, \dots, a_{0}$ are integers. Then smallest positive value of $p$ is

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