Let `veca,vecb,vecc` be three unit vectors such that `3veca+4vecb+5vecc=vec0`. Then which of the following statements is true? (A) `veca` is parrallel to vecb` (B) `veca` is perpendicular to vecb` (C) `veca` is neither parralel nor perpendicular to `vecb` (D) `veca,vecb,vecc` are copalanarA. `veca` is parallel to `vecb`B. `veca` is perpendicular to `vecb`C. `veca` is neither parallel nor perpendicular to `vecb`D. none of these

Let `veca,vecb,vecc` be three unit vectors such that `3veca+4vecb+5vec

1.	Let `veca,vecb,vecc` be three unit vectors such that `3veca+4vecb+5vecc=vec0`. Then which of the following statements is true? (A) `veca` is parrallel to vecb` (B) `veca` is perpendicular to vecb` (C) `veca` is neither parralel nor perpendicular to `vecb` (D) `veca,vecb,vecc` are copalanarA. `veca` is parallel to `vecb`B. `veca` is perpendicular to `vecb`C. `veca` is neither parallel nor perpendicular to `vecb`D. none of these
Answer» Correct Answer - D `3veca + 4vecb + 5vecc =0` Hence `veca, vecb and vecc` are collinear. No other conclusion can be derived from it.

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