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Let `veca=2veci+3vecj+4veck and vecb=3veci+4vecj+5veck`. Find the angle between them. |
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Answer» Correct Answer - `cos^-1((38)/sqrt(1450))` Here `veca=2veci+3veci+4veck` and`vecb=3veci+4vecj+5veck` `veca.vecb=abcostheta` `theta= cos^-1((veca.vecb)/(ab))` =`cos^-1 (2xx3+3xx4+4xx5)/(sqrt(2^2+3^2+4^2)sqrt(3^2+4^2+^2)) =cos^-1 ((38)/(sqrt(29)sqrt(50))) = cos^-1 ((38)/sqrt(1450))` |
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