1.

Let Us Do 2.31. Tthe Hamber nhach i disisible by 9 is(0 201(ii) 3556(ii) 3.206(v) 60126 9uy)99(00 992(iv) none of thesethe sum of its digits is divisible by 9the m of its digits is divisible by 1are div isible by a umber, then their is albo divisible by that numbersum(iv) all the aboveS The swn of two consecutive ol mmbers is ahways dirviuble by0 4(uo Stv) 12The smallest digat which cao replace to make 201 38 divisible by 1is0) 2228 27 425 62s1Q, 9u 2,100's 2624,12.15,6/%,6/92,14340,21,084ind the laggestbumbet is a primeprime momber requirad ho test as a divisoe to determine if the fotlow ingmomber Abo determine ir the mbe is aprime umber: 117, 1smmber219 21, 30 38 421, sA mmer divisle by 3 is also divisiNe by o(a) A mumber dvsble by Is sdhsue ty hech and

Answer»

2.999 because sum of all the digits of 999 is9+9+9=27which is divisible by 3



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