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Let the straight line 2x−y+1=0 touch the hyperbola x2a2−y216=1 at P(α,β). Then the value of 2a2+α−3β is equal to |
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Answer» Let the straight line 2x−y+1=0 touch the hyperbola x2a2−y216=1 at P(α,β). Then the value of 2a2+α−3β is equal to |
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