Let the points of intersections of the lines x−y+1=0,x−2y+3=0 and – InterviewSolution

1.	Let the points of intersections of the lines x−y+1=0,x−2y+3=0 and 2x−5y+11=0 are the mid points of the sides of a triangle ABC. Then the area of the triangle ABC is sq. units.
Answer» Let the points of intersections of the lines $x - y + 1 = 0, x - 2 y + 3 = 0$ and $2 x - 5 y + 11 = 0$ are the mid points of the sides of a triangle $A B C$ . Then the area of the triangle $A B C$ is $sq. units.$

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