Let the locus of foot of the perpendicular drawn from (1,−2) to the family of lines (3+λ)x+(3λ−2)y=8−λ is s=0. If the line's joining origin to the point of intersections of s=0 with the line x+by=1 makes an angle of 60∘ then sum of all possible values of b is

Let the locus of foot of the perpendicular drawn from (1,−2) to the

1.	Let the locus of foot of the perpendicular drawn from (1,−2) to the family of lines (3+λ)x+(3λ−2)y=8−λ is s=0. If the line's joining origin to the point of intersections of s=0 with the line x+by=1 makes an angle of 60∘ then sum of all possible values of b is
Answer» Let the locus of foot of the perpendicular drawn from $(1, - 2)$ to the family of lines $(3 + λ) x + (3 λ - 2) y = 8 - λ$ is $s = 0$ . If the line's joining origin to the point of intersections of $s = 0$ with the line $x + b y = 1$ makes an angle of $60^{\circ}$ then sum of all possible values of $b$ is