Let the four numbers be (a-3d), (a-d), (a+d) & (a+3d). Now According to questionTheir sum : (a-3d)+(a-d)+(a+d)+(a+3d)=28 4a = 28a=7.2.Their product(a-3d)²+(a-d)²+(a+d)²+(a+3d)²=2164a²+20d²=216a² +hting the value of a 49 + 5d² = 545d².

Let the four numbers be (a-3d), (a-d), (a+d) & (a+3d). Now According

1.	Let the four numbers be (a-3d), (a-d), (a+d) & (a+3d). Now According to questionTheir sum : (a-3d)+(a-d)+(a+d)+(a+3d)=28 4a = 28a=7.2.Their product(a-3d)²+(a-d)²+(a+d)²+(a+3d)²=2164a²+20d²=216a² +hting the value of a 49 + 5d² = 545d².
Answer» So, what's the QUESTION here?

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Let the four numbers be (a-3d), (a-d), (a+d) & (a+3d). Now According to questionTheir sum : (a-3d)+(a-d)+(a+d)+(a+3d)=28 4a = 28a=7.2.Their product(a-3d)²+(a-d)²+(a+d)²+(a+3d)²=2164a²+20d²=216a² +hting the value of a 49 + 5d² = 545d².​

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Let the four numbers be (a-3d), (a-d), (a+d) & (a+3d). Now According to questionTheir sum : (a-3d)+(a-d)+(a+d)+(a+3d)=28 4a = 28a=7.2.Their product(a-3d)²+(a-d)²+(a+d)²+(a+3d)²=2164a²+20d²=216a² +hting the value of a 49 + 5d² = 545d².