Let's see who's answer is correct.

1.	Let's see who's answer is correct.
Answer» According to LAW of definite proportions, in a chemical SUBSTANCE, the elements are always present in definite proportions by mass. Given data: Percentage of Ca present in CaCO3 – 40% Percentage of C present in CaCO3 - 12% Percentage of O present in CaCO3 - 48% This means 100g of calcium carbonate contains 40g of Ca, 12g of C and 48g of O. Similarly, 2g of Calcium carbonate contains 40% calcium , 12% CARBON and 48 % oxygen by mass. Let us find the MASSES of Ca, C and O present in 2g of CaCO3. Mass of Calcium present in 2g of CaCO3 = 40/100 X2 = 0.8g Mass of Carbon present in 2g of CaCO3 = 12/100 X 2 = 0.24g Mass of Oxygen present in 2g of CaCO3 = 48/12 X 2 = 0.96g.

Answer»

According to LAW of definite proportions, in a chemical SUBSTANCE, the elements are always present in definite proportions by mass.

Given data:

Percentage of Ca present in CaCO3 – 40%

Percentage of C present in CaCO3 - 12%

Percentage of O present in CaCO3 - 48%

This means 100g of calcium carbonate contains 40g of Ca, 12g of C and 48g of O.

Similarly, 2g of Calcium carbonate contains 40% calcium , 12% CARBON and 48 % oxygen by mass.

Let us find the MASSES of Ca, C and O present in 2g of CaCO3.

Mass of Calcium present in 2g of CaCO3 = 40/100 X2 = 0.8g

Mass of Carbon present in 2g of CaCO3 = 12/100 X 2 = 0.24g

Mass of Oxygen present in 2g of CaCO3 = 48/12 X 2 = 0.96g.

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