Saved Bookmarks
| 1. |
Let `S_n` denotes the sum of the terms of n series `(1lt=nlt=9)` `1+22+333+.....999999999`, isA. `S_(n)-S_(n-1)=(1)/(9)(10^(n)-n^(2)+n)`B. `S_(n)=(1)/(9)(10^(n)-n^(2)+2n-2)`C. `9(S_(n)-S_(n-1))=n(10^(n)-1)`D. None of these |
|
Answer» Correct Answer - C `:. S_(n)=1+22+333+"..."+ubrace(" nnn""...."n)_(" n terms ")` `:. S_(n)-S_(n-1)=ubrace(" nnn""...."n)_(" n times ")=ubrace(111"...."1)_(" n times ")` `=n(10^(n-1)+10^(n-2)+"….."+10+1)=(n(10^(n)-1))/(10-1)` `:. 9(S_(n)-S_(n-1))=n(10^(n)-1)` |
|