1.

Let S be the sum of the first 9 terms of the series: {x+ka}+{x2+(k+2)a}+{x3+(k+4)a}+{x4+(k+6)a}+... where a≠0 and a≠1. If S=x10−x+45a(x−1)x−1, then k is equal to:

Answer»

Let S be the sum of the first 9 terms of the series: {x+ka}+{x2+(k+2)a}+{x3+(k+4)a}+{x4+(k+6)a}+... where a0 and a1. If S=x10x+45a(x1)x1, then k is equal to:



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