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Let PQ be a tangent to a circle at A and AB be a chord. Let C be a point on the circle such that ∠BAC = 54° and ∠BAQ= 62°. Find ∠ABC. |
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Answer» ∠ABC = 180° – (∠BAC + ∠ACB) ∠ABC = 180° – (54° + 62°) = 64° |
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