Saved Bookmarks
| 1. |
{ Let }P(x)=x^3+3ax^2+3bx+c and }P(x)=0} only for }x=α then; }α is also root of equation: } (1) }x^2+2bx+a=0 (2) }ax^2+2bx+c=0 (3) }ax^2+bx+c=0 (4) }ax^2+bx+1=0 |
| Answer» { Let }P(x)=x^3+3ax^2+3bx+c and }P(x)=0} only for }x=α then; }α is also root of equation: } (1) }x^2+2bx+a=0 (2) }ax^2+2bx+c=0 (3) }ax^2+bx+c=0 (4) }ax^2+bx+1=0 | |