Let p,q and r be real numbers (p≠q,r≠0), such that the roots of the equation 1x+p+1x+q=1r are equal in magnitude but opposite in sign, then the sum of squares of these roots is equal to :

Let p,q and r be real numbers (p≠q,r≠0), such that the roots of th

1.	Let p,q and r be real numbers (p≠q,r≠0), such that the roots of the equation 1x+p+1x+q=1r are equal in magnitude but opposite in sign, then the sum of squares of these roots is equal to :
Answer» Let $p, q a n d r$ be real numbers $(p \neq q, r \neq 0)$ , such that the roots of the equation $\frac{1}{x + p} + \frac{1}{x + q} = \frac{1}{r}$ are equal in magnitude but opposite in sign, then the sum of squares of these roots is equal to :

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Let p,q and r be real numbers (p≠q,r≠0), such that the roots of the equation 1x+p+1x+q=1r are equal in magnitude but opposite in sign, then the sum of squares of these roots is equal to :

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